An Introduction to the Differential Calculus By Means of Finite Differences
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In our eReader you can find the full English version of the book. Read An Introduction to the Differential Calculus By Means of Finite Differences Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book An Introduction to the Differential Calculus By Means of Finite Differences
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To quickly assess the difficulty of the text, read a short excerpt:
Example 5. Equation (21).
1 V = x2 du — ^ .
X u Ai A 2 —2 +4. 00 —1. 75 1. 5 2. 25 1. 25 + 0. 50 1. 0 1. 00 0. 75 + 0. 50 —0. 5 0. 25 —0. 25 0. 50 0. 0 0. 00 +0 25 0. 50 +0. 5 0. 25 0. 75 0. 50 1. 0 1. 00 1. 25 0. 50 1. 5 2. 25 1. 75 +0. 50 +2. 0 +4. 00 If we should take the interval as one-fourth, then we should have du 11 -^ = '^^ dx=2x.^^^ X d^u ^ 11 ^. = 2dx^ =2. ^-^ (22: 15. It is seen from these equations that by diminishing the in- terval of the computed dates that the first difference i...s diminished — the second differences ( — ) the third differences ( — ) and so on. N \n J ^ \n J In any computation therefore if we find there are higher differ- ences that are inconveniently large for interpolation or other purposes we can cause them to become less or practically to vanish by diminishing the interval of the computed quantities.
16. Particular values of an equation. Maxima and Minima. The rule in the calculus for this is to differentiate and place the first differential coefficient equal to zero, and solve the equation with respect to x.
What to read after An Introduction to the Differential Calculus By Means of Finite Differences?
You can find similar books in the "Read Also" column, or choose other free books by Roberdeau Buchanan to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Example 5. Equation (21).
1 V = x2 du — ^ .
X u Ai A 2 —2 +4. 00 —1. 75 1. 5 2. 25 1. 25 + 0. 50 1. 0 1. 00 0. 75 + 0. 50 —0. 5 0. 25 —0. 25 0. 50 0. 0 0. 00 +0 25 0. 50 +0. 5 0. 25 0. 75 0. 50 1. 0 1. 00 1. 25 0. 50 1. 5 2. 25 1. 75 +0. 50 +2. 0 +4. 00 If we should take the interval as one-fourth, then we should have du 11 -^ = '^^ dx=2x.^^^ X d^u ^ 11 ^. = 2dx^ =2. ^-^ (22: 15. It is seen from these equations that by diminishing the in- terval of the computed dates that the first difference i...s diminished — the second differences ( — ) the third differences ( — ) and so on. N \n J ^ \n J In any computation therefore if we find there are higher differ- ences that are inconveniently large for interpolation or other purposes we can cause them to become less or practically to vanish by diminishing the interval of the computed quantities.
16. Particular values of an equation. Maxima and Minima. The rule in the calculus for this is to differentiate and place the first differential coefficient equal to zero, and solve the equation with respect to x.
What to read after An Introduction to the Differential Calculus By Means of Finite Differences?
You can find similar books in the "Read Also" column, or choose other free books by Roberdeau Buchanan to read onlineMoreLess
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