Direct And Alternating Current Testing

Cover Direct And Alternating Current Testing
Direct And Alternating Current Testing
Frederick Bedell
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RI and XI ^ drops for different values of primary current, as in Fig. 7, these curves being straight lines. Compare these curves with the cor- responding curves for an alternator, Fig. 2, Exp. 3-8.
For normal full-load current, mark the value of each drop in volts and as per cent, of normal full-load voltage. The per 5-B] TEST BY LOSSES.
165 cent, impedance drop is also called impedance ratio (13, Exp. 3-B).
30. Curves for Copper Losses. Calculate RI^ 2 for -^ J, ^, f, i and ij load. Plotted as
... in Fig. 8, these give the values of 95. 38 121. 9 0. 25 0. 5 0. 75 AMPERES, PRIMARY.
1. 0 FIG. 8. Losses and efficiency of a 2 K. W. Transformer.
the copper loss, including load losses, for different currents; the curve is a parabola.
It is seen that the copper loss, in watts, for a given load is pro- portional to the copper drop, in volts. The copper loss, expressed as a per cent, of rated volt-amperes, is equal to the copper drop, expressed as a per cent, of rated volts.
Per cent, copper loss = RP/EI.


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