A First Course in Nomography
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In our eReader you can find the full English version of the book. Read A First Course in Nomography Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book A First Course in Nomography
What reading level is A First Course in Nomography book?
To quickly assess the difficulty of the text, read a short excerpt:
'pa, v) Take the line through P given by a, h. The equation of this line is Y=h + {b-a)X, where {X, Y) are the coordinates of any point on it. Since P is on this line this equation also holds for (^, >]) the coordinates of P itself. This is true for all lines through P. Hence the a, b intercepts for all lines through P satisfy the single equation f]^b + (b-a)^, I. E.
-a—- 6 + 1=0.
PARALLEL COORDINATES 91 Let then the equation, given to be solved, be written A{x)a-\-B{x)h + 1=^0, so that A{x) an...d B{x) are known functions of x. If there is to be a definite graduation a; at P it follows that the two equations and A{x)a-\-B{x)b + 1=^0, are both true for any number of straight lines through P. This means that the equations are really the same, so that we must have Aix)j, B{x)=-^^, ^ A{x) 1 '^ A{x)-hB{xy ' A{x)-\-B{x) If we eliminate x we obtain an equation between f, V, telling us w^hat the relation between the co- ordinates of P must be if P is to be a graduation in the nomogram, i. E. A point on the x curve/ This relation defines the x curve, which can be plotted.
What to read after A First Course in Nomography?
You can find similar books in the "Read Also" column, or choose other free books by Selig Brodetsky to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
'pa, v) Take the line through P given by a, h. The equation of this line is Y=h + {b-a)X, where {X, Y) are the coordinates of any point on it. Since P is on this line this equation also holds for (^, >]) the coordinates of P itself. This is true for all lines through P. Hence the a, b intercepts for all lines through P satisfy the single equation f]^b + (b-a)^, I. E.
-a—- 6 + 1=0.
PARALLEL COORDINATES 91 Let then the equation, given to be solved, be written A{x)a-\-B{x)h + 1=^0, so that A{x) an...d B{x) are known functions of x. If there is to be a definite graduation a; at P it follows that the two equations and A{x)a-\-B{x)b + 1=^0, are both true for any number of straight lines through P. This means that the equations are really the same, so that we must have Aix)j, B{x)=-^^, ^ A{x) 1 '^ A{x)-hB{xy ' A{x)-\-B{x) If we eliminate x we obtain an equation between f, V, telling us w^hat the relation between the co- ordinates of P must be if P is to be a graduation in the nomogram, i. E. A point on the x curve/ This relation defines the x curve, which can be plotted.
What to read after A First Course in Nomography?
You can find similar books in the "Read Also" column, or choose other free books by Selig Brodetsky to read onlineMoreLess
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