A Second Course in Elementary Algebra

Cover A Second Course in Elementary Algebra
A Second Course in Elementary Algebra
J W a Jacob William Albert Young
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Sec. 100, p. 54.
EXAMPLES (3) (4) 1. Find:. 256 . 32 From the table, 256 = 28, and 32 = 2 5 .
Hence, 256 32 98 = — = 2 8 -5=2 8, 2 5 ' and, according 1 to the table, 2 3 =8.
2. Find: 65536 . 2048 As above, 65536 2048 016 = — = 2 5 = 32.
2ii ORAL EXERCISES By use of the table determine the value of the following :, 1024 „ 32768 32 • 2048 1. • 6. • 5. • 128 1024 512 2 8192 64 - 512 128- 131072 64 ' ' 16-128' ' 64-8-8192 ' 123. Application of Law III, Sec. 101, p. 54.
EXAMPLES 1. Find: 16 3 .
By t
...he table, 16 = 2 4 . (1) Hence, 16 3 = (2 4 ) 3 = 212. (£) and, according to the table, 21' 2 = 4096. (5) 7. V8192.
10.
11. 12.
512 1 .
8. ^4096.
a/32768.
9. ^65536.
a/1024.
76 ELEMENTARY ALGEBRA 2. Find: a/1024.
As above, 1024 = (1024)* = (2 1 *)* _ 25 = 32, according to the table.
3. Find : a/32768.
As above, \^2768 = (215) £ _ 2 3 = 8.
ORAL EXERCISES By use of the table find the value of : 1. 32 3 . 4. 64 2 .
2. 3 5 . 5. 256 2 3. 32 5 . 6. 16 4 .
124. The examples and exercises above show that the laws of exponents furnish a powerful and remarkably easy way of making certain computations.


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