Arithmetic of Electricity; a Practical Treatise On Electrical Calculations of All Kinds Reduced to a Series of Rules, All of the Simplest Forms, And Involving Only Ordinary Arithmetic ..
Arithmetic of Electricity; a Practical Treatise On Electrical Calculations of All Kinds Reduced to a Series of Rules, All of the Simplest Forms, And Involving Only Ordinary Arithmetic ..
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In our eReader you can find the full English version of the book. Read Arithmetic of Electricity; a Practical Treatise On Electrical Calculations of All Kinds Reduced to a Series of Rules, All of the Simplest Forms, And Involving Only Ordinary Arithmetic .. Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Arithmetic of Electricity; a Practical Treatise On Electrical Calculations of All Kinds Reduced to a Series of Rules, All of the Simplest Forms, And Involving Only Ordinary Arithmetic ..
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To quickly assess the difficulty of the text, read a short excerpt:
Hence the current of 90 amperes will cause a rise of 24° F. This is calculated by simple proportion; subtracting 80 from 90 and from 110 gives 10 and 30 as the respective differences and shows 90 to lie at just one-third the distance from 80 to 110. Hence the resulting temperature rise will be at one-third the distance between 18° and 36°. The difference between these last two figures is 18°, one-third of which is 6°. Add this 6° to 18° gives us 24° F. as the answer.
It is often desirable to co...mpute the drop on a feeder carrying a given current; this is done by the following: Rule 76. The drop in volts on any conductor ia found by multiplying- together 10.79, the current in ampere* and it« length in feet, then divide this product by it* area in circular mils.
Example.
What is the drop on a feeder 2,800 feet long, of 105,592 cir. mils area and carrying a current of 125 amperes ?
Solution: 10.79 X 125 X 2,800 = 3,776,500.
Dividing this product by 105,592 gives 35.76 volts drop.
What to read after Arithmetic of Electricity; a Practical Treatise On Electrical Calculations of All Kinds Reduced to a Series of Rules, All of the Simplest Forms, And Involving Only Ordinary Arithmetic ..?
You can find similar books in the "Read Also" column, or choose other free books by Sloane, T. O'conor (Thomas O'conor), 1851-1940 to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Hence the current of 90 amperes will cause a rise of 24° F. This is calculated by simple proportion; subtracting 80 from 90 and from 110 gives 10 and 30 as the respective differences and shows 90 to lie at just one-third the distance from 80 to 110. Hence the resulting temperature rise will be at one-third the distance between 18° and 36°. The difference between these last two figures is 18°, one-third of which is 6°. Add this 6° to 18° gives us 24° F. as the answer.
It is often desirable to co...mpute the drop on a feeder carrying a given current; this is done by the following: Rule 76. The drop in volts on any conductor ia found by multiplying- together 10.79, the current in ampere* and it« length in feet, then divide this product by it* area in circular mils.
Example.
What is the drop on a feeder 2,800 feet long, of 105,592 cir. mils area and carrying a current of 125 amperes ?
Solution: 10.79 X 125 X 2,800 = 3,776,500.
Dividing this product by 105,592 gives 35.76 volts drop.
What to read after Arithmetic of Electricity; a Practical Treatise On Electrical Calculations of All Kinds Reduced to a Series of Rules, All of the Simplest Forms, And Involving Only Ordinary Arithmetic ..?
You can find similar books in the "Read Also" column, or choose other free books by Sloane, T. O'conor (Thomas O'conor), 1851-1940 to read onlineMoreLess
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