Automatic Control of Electric Flat Irons : Also Proposed Methods

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Then Ik = \j fk2+ lf2j i^ ' - ^f'k'2 + (if + ff»)^ °^ kk' = ^2 + if2 _^f'ij«2 + (If + ff«)2 V 13.
From which we obtain for largest k 'k that f'k' is equal to If + f 'f = If.
Which expressed in words is, "For the greatest movement of the point k the links fk and gk must each be equal in length to the distance between the points at which they are fastened to the base plus half of the total expansion of the base along the line connect- ing these points.
Let us now focus our attention on the moveme
...nt of the point j or Fig. 2; the movement of k with respect to a transverse axis through r is kk'-b where b is the longitudinal expansion of the base C.
Prom the previous mathematics.
Length of kj = jr s kr ♦ kk ' -f b 2 2 movement of j to j is 1^ (kr ♦ kk' + b)2 - kr 2 . jj », n F.3.3.
yk tf^ Fi^. -^ 16.
CONSTRUCTION There being no irons available that would afford ample space within to house our mechanism, we constructed two irons having the dimensions as shown in Fig* 3.
With the thoughts of using the base of the iron as the element C of the mechanism, we set about to determine whether or not the movement of j with this arrangement would be sufficiently large enough as to be of practical use.


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