Differential Equations; a Short Course for Engineering Students
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In our eReader you can find the full English version of the book. Read Differential Equations; a Short Course for Engineering Students Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Differential Equations; a Short Course for Engineering Students
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To quickly assess the difficulty of the text, read a short excerpt:
Take the equation .(^y+y=o. (1) This may be written ^+4^=0.
Differentiating, dividing by dy and solving the linear thus formed 1 iy^_1fdp_^ ,2) p^ p^ p^dy „dp . Zp-'i- __ 1 ,3, -P~^dy^ 2v 13;3"' * ' Substituting the value of /— 1 in (4) in equation (1) we get xy + 20/*+ Cy + l^O. (5) That (5) is the integral of (1) may be shown in the usual way by differentiating once and eliminating C.
1 dx In problems of this kind, instead of using — for—— to introduce 6 dv 26 EQUATIONS SOLVABLE FOR X.
anothe...r new variable, the letter q is generally used in works on dif- dx ferential equations for——. The problem is then exactly the same as dy that of Art. 20, except that x and y change places. Using this nota- tion, equation ( 1 ) of the preceding paragraph becomes ;i:-|-V/=0. (1).
Differentiating and dividing by dji 9 + 3?=y + 20/S ^ = 0. (2> ay From (3) we get the linear dq _,Zq _ _ J_ / 3 V dy ^ 2y 2y^' gy =y -\-C. ^'' Substituting (4) in (1) we get the same result as in the preceding case.
What to read after Differential Equations; a Short Course for Engineering Students?
You can find similar books in the "Read Also" column, or choose other free books by James E James Ellsworth Boyd to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Take the equation .(^y+y=o. (1) This may be written ^+4^=0.
Differentiating, dividing by dy and solving the linear thus formed 1 iy^_1fdp_^ ,2) p^ p^ p^dy „dp . Zp-'i- __ 1 ,3, -P~^dy^ 2v 13;3"' * ' Substituting the value of /— 1 in (4) in equation (1) we get xy + 20/*+ Cy + l^O. (5) That (5) is the integral of (1) may be shown in the usual way by differentiating once and eliminating C.
1 dx In problems of this kind, instead of using — for—— to introduce 6 dv 26 EQUATIONS SOLVABLE FOR X.
anothe...r new variable, the letter q is generally used in works on dif- dx ferential equations for——. The problem is then exactly the same as dy that of Art. 20, except that x and y change places. Using this nota- tion, equation ( 1 ) of the preceding paragraph becomes ;i:-|-V/=0. (1).
Differentiating and dividing by dji 9 + 3?=y + 20/S ^ = 0. (2> ay From (3) we get the linear dq _,Zq _ _ J_ / 3 V dy ^ 2y 2y^' gy =y -\-C. ^'' Substituting (4) in (1) we get the same result as in the preceding case.
What to read after Differential Equations; a Short Course for Engineering Students?
You can find similar books in the "Read Also" column, or choose other free books by James E James Ellsworth Boyd to read onlineMoreLess
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