Elements of Mechanics: for the Use of Colleges, Academies, And High Schools
Elements of Mechanics: for the Use of Colleges, Academies, And High Schools
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In our eReader you can find the full English version of the book. Read Elements of Mechanics: for the Use of Colleges, Academies, And High Schools Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Elements of Mechanics: for the Use of Colleges, Academies, And High Schools
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To quickly assess the difficulty of the text, read a short excerpt:
From Equation (129), we see that the normal component of the centrifugal force is equal to the centrifugal force at the equator multiplied by the square of the cosine of the latitude of the place.
This component is directly opposed to gravity, and, con* sequently, tends to diminish the weight of all bodies on the surface of the earth. The value of this component is greatest at the equator, and diminishes towards the poles, where it becomes equal to 0. From the action of the normal component of ...the centrifugal force, and fi'om the flattened form of the earth due to the tangential component bringing the polar regions nearer the centre of the earth, the measured force of gravity ought to increase in passing from the equator towards the poles. This is found, by observation, to be the case.
The radius of the earth at the equator is found, by measurement, to be about 3962.8 miles, which, multiplied by 251-, will give the entire circumference of the equator. If this be divided by the number of seconds iti a day, 86400, we find the value of v.
What to read after Elements of Mechanics: for the Use of Colleges, Academies, And High Schools?
You can find similar books in the "Read Also" column, or choose other free books by William G William Guy Peck to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
From Equation (129), we see that the normal component of the centrifugal force is equal to the centrifugal force at the equator multiplied by the square of the cosine of the latitude of the place.
This component is directly opposed to gravity, and, con* sequently, tends to diminish the weight of all bodies on the surface of the earth. The value of this component is greatest at the equator, and diminishes towards the poles, where it becomes equal to 0. From the action of the normal component of ...the centrifugal force, and fi'om the flattened form of the earth due to the tangential component bringing the polar regions nearer the centre of the earth, the measured force of gravity ought to increase in passing from the equator towards the poles. This is found, by observation, to be the case.
The radius of the earth at the equator is found, by measurement, to be about 3962.8 miles, which, multiplied by 251-, will give the entire circumference of the equator. If this be divided by the number of seconds iti a day, 86400, we find the value of v.
What to read after Elements of Mechanics: for the Use of Colleges, Academies, And High Schools?
You can find similar books in the "Read Also" column, or choose other free books by William G William Guy Peck to read onlineMoreLess
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