Mechanics a School Course
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In our eReader you can find the full English version of the book. Read Mechanics a School Course Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Mechanics a School Course
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However there is less kinetic energy after impact than before, owing to the loss already alluded to. If the kinetic energies before and after impact are E L, E 2, then E - E 2 is the lost energy. If e is the kinetic energy at the middle of the impact, E l e is the energy which ought to have been stored up as potential energy. The lost energy is a fraction of this which depends on the materials of the bodies. Let k be this fraction. Then E i -E, = k(E i -e], which gives E. 2 e = (l-k)(E l e).
No...w EI = \ mi Uj 2 + 5 w 2 w a 2 E 2 = % nii v* + | ra 2 vj and, if F be the velocity of the two spheres at the middle of their contact, e = ^(m 1 + m 2 ) F 2 .
But mj UL + m 2 u 2 = m^ v t + m 2 v. 2 = (m^ + m 2 ) F (see 53), i 1 2 1 ' 2 Als This gives e = \/\-k.
(i) When the coefficient of restitution is -{g, what fraction of the kinetic energy is lost at impact?
(ii) If the loss of kinetic energy at impact is 10 per cent. , what is the ratio of the relative velocities before and after impact?
136.
What to read after Mechanics a School Course?
You can find similar books in the "Read Also" column, or choose other free books by W D Eggar to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
However there is less kinetic energy after impact than before, owing to the loss already alluded to. If the kinetic energies before and after impact are E L, E 2, then E - E 2 is the lost energy. If e is the kinetic energy at the middle of the impact, E l e is the energy which ought to have been stored up as potential energy. The lost energy is a fraction of this which depends on the materials of the bodies. Let k be this fraction. Then E i -E, = k(E i -e], which gives E. 2 e = (l-k)(E l e).
No...w EI = \ mi Uj 2 + 5 w 2 w a 2 E 2 = % nii v* + | ra 2 vj and, if F be the velocity of the two spheres at the middle of their contact, e = ^(m 1 + m 2 ) F 2 .
But mj UL + m 2 u 2 = m^ v t + m 2 v. 2 = (m^ + m 2 ) F (see 53), i 1 2 1 ' 2 Als This gives e = \/\-k.
(i) When the coefficient of restitution is -{g, what fraction of the kinetic energy is lost at impact?
(ii) If the loss of kinetic energy at impact is 10 per cent. , what is the ratio of the relative velocities before and after impact?
136.
What to read after Mechanics a School Course?
You can find similar books in the "Read Also" column, or choose other free books by W D Eggar to read onlineMoreLess
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