Problems in Physical Chemistry With Practical Applications
Problems in Physical Chemistry With Practical Applications
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In another experiment at the same temperature, and p 720 mm. , 73 per cent, of an original volume of HCl (34*1 c. C. ) was transformed at equilibrium. If K p = 2*0, find the initial volume of oxygen.
Answer 15*9 c. C.
Haber (" Thermodynamics of Technical Gas Reactions, " p. 181).
16. A mixture of 80$, 0% and jV 2 in the molecular pro- portions 2*62 : 1 : 3*76 was passed through a silica tube at 1, 001 absolute (Bodenstein und Pohl, Zeitsch. Elektro- chem. (1905), 2, 273). The resulting equilibr...ium mixture rapidly cooled was found to contain : SO* : S0 3 : 2 = 33*9 : 17'5 : 10'9 mols. P = 759 mm. Throughout.
Find the equilibrium constant K c, and an expression for the percentage yield ^^ - which would be obtained if JV 2 were absent from the mixture of 2 and 2 in the above ratio. The combination is effected at 760 mm.
Note The amount of nitrogen associated with the resul- tant mixture must be found and included in the total number of molecules (N) (see equation (6) p. 141).
*X x N Q, x / ~N~~ ' To find the amount x of O 2 transformed, if there is no PKOBLEMS IN PHYSICAL CHEMISTEY 153 N z, equate the product 2*62 - 2 x etc.
What to read after Problems in Physical Chemistry With Practical Applications?
You can find similar books in the "Read Also" column, or choose other free books by Edmund Bridges Rudhall Prideaux to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
In another experiment at the same temperature, and p 720 mm. , 73 per cent, of an original volume of HCl (34*1 c. C. ) was transformed at equilibrium. If K p = 2*0, find the initial volume of oxygen.
Answer 15*9 c. C.
Haber (" Thermodynamics of Technical Gas Reactions, " p. 181).
16. A mixture of 80$, 0% and jV 2 in the molecular pro- portions 2*62 : 1 : 3*76 was passed through a silica tube at 1, 001 absolute (Bodenstein und Pohl, Zeitsch. Elektro- chem. (1905), 2, 273). The resulting equilibr...ium mixture rapidly cooled was found to contain : SO* : S0 3 : 2 = 33*9 : 17'5 : 10'9 mols. P = 759 mm. Throughout.
Find the equilibrium constant K c, and an expression for the percentage yield ^^ - which would be obtained if JV 2 were absent from the mixture of 2 and 2 in the above ratio. The combination is effected at 760 mm.
Note The amount of nitrogen associated with the resul- tant mixture must be found and included in the total number of molecules (N) (see equation (6) p. 141).
*X x N Q, x / ~N~~ ' To find the amount x of O 2 transformed, if there is no PKOBLEMS IN PHYSICAL CHEMISTEY 153 N z, equate the product 2*62 - 2 x etc.
What to read after Problems in Physical Chemistry With Practical Applications?
You can find similar books in the "Read Also" column, or choose other free books by Edmund Bridges Rudhall Prideaux to read onlineMoreLess
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