Second Year Mathematics for Secondary Schools
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In our eReader you can find the full English version of the book. Read Second Year Mathematics for Secondary Schools Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book Second Year Mathematics for Secondary Schools
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Thus if we are able to find the area of a parallelogram, the area of the triangle is found. FIG. 245 FIG. 246 Fig. 246 shows how the area of a parallelogram can easily be compared with the area of a rectangle. The question arises, whether the rectangle and the parallelogram of Fig. 246 are equal to each other, and, more generally, under what con- ditions such figures are equal to each other. This question is answered by Exercise i, 229. If we know how to compare parallelograms, we can com- pare... parallelograms with rectangles because a rectangle is a special case of a parallelogram. 228. We have thus the following chain of problems leading to the problem of computing the area of the triangle: (1) to compare parallelograms (2) to compare a parallelogram and a rectangle (3) to compute the area of a rectangle (4) to compute the area of a parallelogram (5) to compare a parallelogram and a triangle (6) to compute the area of a triangle. PROPOSITION I 229. Theorem: Parallelograms having equal bases and equal altitudes are equal.
What to read after Second Year Mathematics for Secondary Schools?
You can find similar books in the "Read Also" column, or choose other free books by George William Myers to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
Thus if we are able to find the area of a parallelogram, the area of the triangle is found. FIG. 245 FIG. 246 Fig. 246 shows how the area of a parallelogram can easily be compared with the area of a rectangle. The question arises, whether the rectangle and the parallelogram of Fig. 246 are equal to each other, and, more generally, under what con- ditions such figures are equal to each other. This question is answered by Exercise i, 229. If we know how to compare parallelograms, we can com- pare... parallelograms with rectangles because a rectangle is a special case of a parallelogram. 228. We have thus the following chain of problems leading to the problem of computing the area of the triangle: (1) to compare parallelograms (2) to compare a parallelogram and a rectangle (3) to compute the area of a rectangle (4) to compute the area of a parallelogram (5) to compare a parallelogram and a triangle (6) to compute the area of a triangle. PROPOSITION I 229. Theorem: Parallelograms having equal bases and equal altitudes are equal.
What to read after Second Year Mathematics for Secondary Schools?
You can find similar books in the "Read Also" column, or choose other free books by George William Myers to read onlineMoreLess
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