Steam Turbines

Cover Steam Turbines
Steam Turbines
James Cran
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W. And is operating at full load, the output in electrical horsepower is 2000 X 1. 34 = 2680. Taking the efficiency of the generator as 0. 95, . The B. H. P. Of the turbine will be 2680 + 0. 95 = 2821; and 40, 000 -f- 2821 = 14. 2 pounds of steam per hour per B. H. P. , from which a com- parison of the steam economy of the two machines may be made.
It is sometimes desired to compute the steam consumption per indi- cated horsepower of a reciprocating engine which might replace a tur- bine operat
...ing under given conditions. For example, in the problem just solved, find the indicated horsepower and water-rate of a recipro- cating engine which would replace the turbine and do the same amount of work, with the same total steam consumption. The first step is to find the brake horsepower required to drive the generator. This was shown to be 2821. Assuming an engine efficiency of 0. 95, the indicated horsepower is 2821 -=- 0. 95 = 3000 (in round numbers), from which the water rate is found to be 40, 000 * 3000 = 13.

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