The Inverse Scattering Problem

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The Inverse Scattering Problem
Irvin W Kay
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3 )♦ Further, a solution u(k, x) of (2. 1) is given by (3. 2) when u (k, x) satisfies (3»l). The function u(k, x) given by (3. 2) is evidently continuous, and because K(x, y) is continuous and partial derivatives of K(x, y) are piecewise continuous, u(k, x) has a continuous derivative.
For the second part of the proof we must show that the solution of (2. 1) given by (3. 2) when u^(k, x) - e^^ + b(x) e"^*"' is the one which has ikx the behavior u(k, x) ~ a(k) e for x -»• +oo. It is difficult to
... ascertain directly the behavior as x -»- +oo of a solution u(k, x) of (2. 1) when u(k, x) is given in the form (3. 2), but its behavior as x -»• -oo is just u (k, x). We shall therefore investigate the character of our solution u(k, x), which aj>- preaches e +b(k) e as x -► -oo, by comparing it with that (unique) solution u(k, x) of (2. 1) iirtiich has the behavior e~ as x -»• -oo. We know: if and only if (U. 6) i / u(k, x) u(k, y) dk - 5(x-y), u(k, x) has the behavior (U. 7) u(k, x).

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