The Normal, Or, Methods of Teaching the Common Branches: Orthoepy, Orthography, Grammar ...
The Normal, Or, Methods of Teaching the Common Branches: Orthoepy, Orthography, Grammar ...
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In our eReader you can find the full English version of the book. Read The Normal, Or, Methods of Teaching the Common Branches: Orthoepy, Orthography, Grammar ... Online - link to read the book on full screen. Our eReader also allows you to upload and read Pdf, Txt, ePub and fb2 books. In the Mini eReder on the page below you can quickly view all pages of the book - Read Book The Normal, Or, Methods of Teaching the Common Branches: Orthoepy, Orthography, Grammar ...
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To quickly assess the difficulty of the text, read a short excerpt:
23, 33, 43, 53.
By the first ru'a we have 3xllx23'x43x53=a L. CM.
THEORETICAL ARITHMETIC.
323 By the second rule we have 53x43x3x11x23 =L. CM.
72.
Demonstration of the rule for obtaining the L.
C. M. by division.
Take the numbers 6, 8, 9, 12, 15, 18, 20, 24, 25 ; divide these by 2, and we shall obtain the quotients and undivided numbers, 3, 4, 9, 6, 15, 9, 10, 12, 25. Now this divisor 2 will answer for all the first powers of 2 contained in any of the given numbers; consequently those first pow...ers of 2 are all rejected, and this divisor 2 is retained for them in the L. C. M.
Dividing again by 2 we shall obtain the quo- tients and undivided numbers, 3, 2, 9, 3, 15, 9, 5, 6, 25. This second divisor 2 will answer for all the second factors of 2 in any of the given num- bers. It is therefore retained, a? a factor of the L. C. M. Dividing again by 2 we obtain 3, 1, 9, 3, 15, 9, 5, 3, 25. This third divisor 2 answers for all the third factors of 2 contained in any given numbers. Hence it is obvious that dividing by the several prime factors as long as two or more of the given numbers can be divided without a frac- tional quotient, is merely for the purpose of re- jecting superfluous factors, and retaining the necessary factors, for the L.
What to read after The Normal, Or, Methods of Teaching the Common Branches: Orthoepy, Orthography, Grammar ...?
You can find similar books in the "Read Also" column, or choose other free books by Alfred Holbrook to read onlineMoreLess
To quickly assess the difficulty of the text, read a short excerpt:
23, 33, 43, 53.
By the first ru'a we have 3xllx23'x43x53=a L. CM.
THEORETICAL ARITHMETIC.
323 By the second rule we have 53x43x3x11x23 =L. CM.
72.
Demonstration of the rule for obtaining the L.
C. M. by division.
Take the numbers 6, 8, 9, 12, 15, 18, 20, 24, 25 ; divide these by 2, and we shall obtain the quotients and undivided numbers, 3, 4, 9, 6, 15, 9, 10, 12, 25. Now this divisor 2 will answer for all the first powers of 2 contained in any of the given numbers; consequently those first pow...ers of 2 are all rejected, and this divisor 2 is retained for them in the L. C. M.
Dividing again by 2 we shall obtain the quo- tients and undivided numbers, 3, 2, 9, 3, 15, 9, 5, 6, 25. This second divisor 2 will answer for all the second factors of 2 in any of the given num- bers. It is therefore retained, a? a factor of the L. C. M. Dividing again by 2 we obtain 3, 1, 9, 3, 15, 9, 5, 3, 25. This third divisor 2 answers for all the third factors of 2 contained in any given numbers. Hence it is obvious that dividing by the several prime factors as long as two or more of the given numbers can be divided without a frac- tional quotient, is merely for the purpose of re- jecting superfluous factors, and retaining the necessary factors, for the L.
What to read after The Normal, Or, Methods of Teaching the Common Branches: Orthoepy, Orthography, Grammar ...?
You can find similar books in the "Read Also" column, or choose other free books by Alfred Holbrook to read onlineMoreLess
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