The Theory of Structures

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Pitch = 4 inches.
2. A cross girder for a bridge carryivy two lines of rails is 27 feet long and 24 inches deep ; ^ it carries four concentrated loads, f \ i^.-.4»...^.J ! ^ a \ each weighing 30 tons ; the two ^ I -^ -^t- ^^ -©J loads on one side of the centre i 1 -^y ^hQ? -©• of span being symmetrical with \ \ ^ "^^ ^ the two on the other side. Deter- ' " ^ig, 115.
mine the pitch of the angle rivets if the diameter of rivet is J inch.
Thickness of web = J inch.
Assume same working stresses as
...in last example.
Eivets in double shear.
Shear strength of one rivet = 2x0-6x6 = 7-2 tons.
Bearing strength of rivet on web plate = | x J x 12 = 5-25 tons.
Least B = 5-25 tons.
Shearing force at ends, F = 2 x 30 = 60 tons.
From (3) ^ 5-25x24 ^ 2-1 inches.
^ 60 This pitch is too small for a single line of rivets.
Therefore we must use angles 4Y x 4^" x Y with two rows of rivets placed zig-zag (Fig. 115).
Now, as there are two rivets in each pitch, m ^ 2x5-25x24 ^ ^.^ .^^j^^^ ^ F 60 Pitch = 4 inches.


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